Into space

Reflect, then slide by half of something

A glide's slide must double to a lattice vector, which leaves three candidates in any plane and a fourth that exists only where centring has already made a half-diagonal into a lattice vector. Five letters, and the fifth is the one the enumeration explains.

Assumes Turning and climbing at once and Centring, and why cm is not pm.

A glide reflects across a plane and then slides along it. The plane’s job is done by the reflection; the slide is the part that has to be justified, and justifying it enumerates the whole family.

The five kinds of glide plane. All five glide letters: a, sliding by a/2; b, sliding by b/2; c, sliding by c/2; n, sliding by (a+b)/2, (b+c)/2 or (a+c)/2; d, sliding by (a+b)/4, (b+c)/4 or (a+c)/4. 3 of those drawn are axial — the slide is half of a single cell vector lying in the plane. A glide's square is a pure translation, so its slide can only be half of a lattice vector, and the quarter-cell d glide exists only where centring has already made the half-diagonal a lattice vector.
Fig. 1 The five. Each panel shows a point, the plane, and the point’s image after reflecting and sliding. The three on the left slide by half a cell edge lying in the plane; the fourth slides by half a face diagonal; the fifth slides by a quarter of one, and it is the only one that cannot exist in a primitive lattice.

The constraint

Apply a glide twice. The reflections cancel — reflecting across the same plane twice is the identity — and the two slides add. So the square of a glide is a pure translation by twice its slide, and that translation has to be a lattice vector, because a symmetry with no rotation part is a lattice translation.

The slide is therefore half of a lattice vector, lying in the plane.

That is the whole constraint and it is worth noticing how much it rules out. The slide cannot be a third of anything, or a quarter, or an arbitrary fraction — the doubling condition admits halves and nothing else. It cannot point out of the plane, because a glide reflects across the plane and a component perpendicular to it would be removed by moving the origin, which is exactly what “the plane can be put anywhere along its own normal” means.

Three candidates, and then a fourth

Take a plane spanned by two cell vectors u and v. Which lattice vectors lie in it? Every integer combination of u and v, so the halves available are u/2, v/2 and (u + v)/2 — three, and no more, because (uv)/2 differs from (u + v)/2 by the lattice vector v and is the same operation.

Three slides, three glides. The first two are the axial glides, named for whichever cell vector they slide along: a, b or c depending on the plane. The third is the diagonal glide, written n, sliding along half a face diagonal.

3 glide planes. 3 of the five glide letters: a, sliding by a/2; c, sliding by c/2; n, sliding by (a+b)/2, (b+c)/2 or (a+c)/2. 2 of those drawn are axial — the slide is half of a single cell vector lying in the plane. A glide's square is a pure translation, so its slide can only be half of a lattice vector, and the quarter-cell d glide exists only where centring has already made the half-diagonal a lattice vector.
Fig. 2 The three a primitive lattice offers. The two axial glides slide along one cell edge; the diagonal glide slides along the sum of both, at half. Nothing else in the plane doubles to a lattice vector, so the enumeration for a primitive lattice stops here.

Now centre the lattice. In an F-centred cell, (u + v)/2 is itself a lattice vector — that is what face centring means. So the doubling condition, which asks that twice the slide be a lattice vector, is satisfied by half of it: (u + v)/4.

That is the d glide, the diamond glide, and the enumeration has just explained the thing about it that is usually stated as a rule. It appears only in F- and I-centred groups because in a primitive lattice its square is not a lattice translation, so it is not a symmetry of anything periodic.

The fifth letter, and where it lives

The d glide is rare and its structures are famous. It is the glide of diamond itself — space group Fd3̅m, where the two interpenetrating face-centred carbon sublattices are related by a quarter-diagonal glide — and of the spinels, and of silicon and germanium, which have diamond’s structure.

The hk0 layer of Fddd. The hk0 reflections of Fddd out to 5 in each index, with each spot decided by summing the structure factor over the group's operations: 12 survive and 108 vanish identically, whatever the atoms are. The pattern of holes is the condition hkl: h, k, l all even or all odd and hk0: h+k divisible by four, read back off the spots rather than imposed on them.
Fig. 3 What a d glide does to a diffraction pattern, computed from the structure-factor sum rather than looked up. In the hk0 layer of Fddd only reflections with h + k divisible by four survive — a quarter condition rather than a half, which is the diffraction signature of the quarter-cell slide. No other operation produces a condition modulo four.

That is worth dwelling on, because it is the clearest case in this field of two independent routes reaching the same fact. The enumeration says the d glide slides by a quarter because centring makes the half a lattice vector. The diffraction calculation, which knows nothing about glides and only sums exponentials over the group’s operations, produces a condition modulo four. Neither derivation mentions the other and they agree.

Why there are three axial letters and not two

A small point of bookkeeping that is worth getting right, because the numbers do not quite say what they look like.

Any given plane contains exactly two cell directions, so it offers exactly two axial glides. A plane perpendicular to c contains a and b, so it can be an a glide or a b glide and cannot be a c glide — a c glide perpendicular to c would slide out of its own plane, which is not a glide at all.

So the three letters a, b and c are not three glides available in one place. They are one mechanism — slide by half a cell edge lying in the plane — named by which edge, and which two of the three letters are available depends on which way the plane faces. Counting them as three is a count of symbols.

2 glide planes. 2 of the five glide letters: a, sliding by a/2; b, sliding by b/2. 2 of those drawn are axial — the slide is half of a single cell vector lying in the plane. A glide's square is a pure translation, so its slide can only be half of a lattice vector, and the quarter-cell d glide exists only where centring has already made the half-diagonal a lattice vector.
Fig. 4 The two axial glides available to one plane, drawn together. Both slide by half a cell edge; the choice is which edge, and it is a choice between the two that lie in the plane. The third letter belongs to planes facing a different way.

That matters for reading a symbol. In Pbcm the three letters are in the three orthorhombic positions, so b is a plane perpendicular to a sliding along b, c is a plane perpendicular to b sliding along c, and m is a plain mirror perpendicular to c. Each letter has to be legal for its position, and a symbol like Paba is not a symbol at all because the first position cannot carry an a.

The plane already had one of these

The plane has a glide, and this site has an essay about it whose finding transfers exactly.

In two dimensions the plane’s glide slides by half a cell edge, and there is only one kind, because a line has only one direction to slide along. The rectangular lattice offers u/2 and nothing else; the diagonal case does not arise because the “plane” is a line and it contains one lattice direction.

What the cm essay found was subtler and it is worth repeating here in three dimensions. cm’s glide is a fact about the cell, not about the pattern. Described on the conventional centred rectangular cell, cm has four operations and one of them is a glide. Described on the primitive rhombic cell of the same lattice, it has two operations and neither is a glide, because the centring translation is a lattice vector in that basis and the “glide” is the mirror composed with it.

The same thing happens in space, wherever a centring translation lies in a mirror plane. A mirror in a C-centred group, composed with the (½, ½, 0) centring, gives a glide — and whether that counts as a distinct operation depends on which cell is being used. The round trip here treats centring translations as operations of the group, so the answer is always given with respect to the conventional cell, and the conventional cell is stated.

The glide a centring adds without being asked. 4 space groups, each entered as a few generators and then closed. The third column counts the planes the generators actually declare and the fourth counts the planes the closure holds, which are different numbers: Ccmm declares none and ends up with 6, Fddd declares none and ends up with 12. The last column takes each mirror in the closure and composes it with each centring translation: 3 of those products across these groups are glides, and every one is checked to be an operation the group already has, since a centring vector is one of its own translations. The slide that appears is the centring vector's part that the reflection fixes, and the part it reverses moves the plane instead — so the acquired glide shares the mirror's plane exactly when the centring vector lies wholly inside it, which is checked against the two located positions. The primitive group is the control: no centring vector, nothing to compose with, no glide acquired.
Fig. 5 The same thing in space, counted. Each group is entered as a few generators and then closed, and the two middle columns are the planes the generators declare against the planes the closure holds — Ccmm declares none and ends up with six, Fddd declares none and ends up with twelve. The last column takes each mirror in the closure and composes it with each centring translation: three of those products across these groups are glides, and each is checked to be an operation the group already has, since a centring vector is one of its own translations. Ccmm’s mirror perpendicular to c gains an n glide on its own plane, because the C-centring vector lies wholly inside that plane; Cm’s gains an a glide at another height, because there the centring vector has a component across the plane and that part moves the plane rather than sliding along it. Pm is the control — no centring vector, nothing to compose with.

Where the notation puts the letter

In a Hermann–Mauguin symbol a glide’s letter names the direction it slides, and the position in the symbol names the direction the plane faces. Those are two different directions and confusing them is the single commonest mistake in reading these symbols.

Pna2₁ has three positions after the lattice letter, one per axis of an orthorhombic cell. The first is n: perpendicular to a, a plane that slides along a face diagonal. The second is a: perpendicular to b, a plane sliding along the a direction. The third is the polar axis, along c, carrying a 2₁ screw.

So the letter a in that symbol is in the second position and does not refer to the a axis as a plane normal — it refers to the a axis as a slide direction, in a plane that faces b. The symbol reads position-first and letter-second, and reading it letter-first gives a plausible and wrong answer.

Pna2₁, in the two diagrams the Tables print. Space group Pna2₁, number 33, projected down c on a primitive orthorhombic cell. The symmetry elements drawn: 4 glide planes, 4 2₁ screw axes. 4 general positions, the orbit of one point, each labelled with its height along c and marked with a comma where the operation that produced it reversed handedness.
Fig. 6 The group in question. The dashed lines are the two glides, at right angles to each other; the marks with tails are the screw the two glides compose to. Reading the diagram against the symbol is the exercise, and the thing to check is which plane is which.

Composition, and the glide nobody chose

The other way to get a glide is to not ask for one.

A rotation composed with a mirror gives a reflection; a rotation composed with a glide gives another glide, or sometimes a mirror. And a mirror composed with a translation lying in its plane gives a glide directly, with no rotation involved — which is exactly what a centring vector does when it lies in a mirror plane.

That is the cm mechanism and it is common in space. Any C-centred group with a mirror perpendicular to c acquires a glide, because the centring vector (½, ½, 0) lies in that plane, and the mirror composed with it slides by half a face diagonal — an n glide. Nobody put it there.

The consequence for the machinery here is that a group is never described by a list of its operations written down in advance. The generators are stated, the closure is run, and whatever the closure produces is what the group has. A list of operations typed out by hand would be missing precisely the ones that are hardest to anticipate, which is the subject of the next rung.

Each slide's condition, derived and then measured. The five glide letters with the slide each carries, and the condition that slide forces on the reflections in its own plane's zone: the plane holds two operations whose contributions differ by a phase of 2πh·s, so they cancel unless h·s is a whole number, which makes the modulus the denominator of the slide. Four of the five slide by a half and halve their zone; the d glide slides by a quarter and leaves only every fourth reflection. Below, the same conditions arrived at from the other end — the absences of 6 real groups, summed over each group's own operations with no mention of glides, searched for the modulus that describes them. 1 of the groups shows a condition modulo four and it is exactly the one with a d glide in it; no group without one does, so the signature belongs to the quarter-cell slide and not to the centring that permits it.
Fig. 7 The same condition twice, from the two ends. Above, what each slide implies on its own: the plane holds two operations whose contributions to a reflection in its zone differ by a phase of 2πh·s, so they cancel unless h·s is a whole number, which makes the modulus the denominator of the slide. Four letters slide by a half and halve their zone; d slides by a quarter and leaves only every fourth. Below, the absences of six real groups, summed over each group’s own operations with no mention of glides and then searched for the modulus that describes them. One group shows a condition modulo four and it is the one with a d glide; no group without one does. What each says is a condition on a zone — a plane of reflections — rather than on a row, which is the diffraction signature of a plane as against an axis.

What a glide costs a structure

Like a screw, a glide has no fixed point — a point on the plane reflects to itself and then slides, so it moves. That means no atom sits on a glide plane, and a glide contributes nothing to the list of special positions.

The consequence is the same arithmetic the screw essay reached. A group whose only non-translational operations are glides acts freely, and every orbit has the full order of the group; the number of formula units in the cell is a multiple of that order, with no exceptions available.

A mirror, by contrast, is generous. Every point of a mirror plane is fixed by it, so a mirror gives a two-dimensional sheet of special positions, and a molecule with its own mirror symmetry can sit on one and halve its contribution to the cell. Mirrors are the most abundant source of special positions in any group that has them, which the Wyckoff analysis found in the plane too: sixty of a hundred and forty-four sample points in p4m lie on a mirror, against two at the fourfold centres, because a line has room and a point does not.

So the difference between Pmm2 and Pcc2 is not decorative. One offers two perpendicular sheets of special positions and the other offers none, and a molecule choosing between them is choosing whether it can economise.

Two glides at right angles make a screw

The last thing worth showing is what glides do to each other, because it is the mechanism behind four of the ten groups in the mm2 enumeration and it is not obvious.

Compose two glides whose planes are perpendicular. The two reflections compose to a two-fold rotation about the line where the planes meet — that part is the same as for two mirrors. The two slides add, and the component along the intersection line survives, because both slides lie in their own planes and the intersection lies in both.

So if either glide slides along the line where the planes meet, the product is a two-fold screw about that line.

Two glides at right angles, and whether the product climbs. Every pair of perpendicular planes in Pba2, Pna2₁, Pbca and Pnma, composed from the groups' own operations, with the product classified from its own intrinsic translation. The two reflections give a two-fold rotation about the line where the planes meet; the two slides add, and only the part along that line survives, because each slide lies in its own plane and the line lies in both. So the product is a screw exactly when one slide has a component along the line and the other has none — 7 of the 8 pairs here. Two components add to a whole cell, which is a lattice translation, so both halves give a plain rotation just as both zeroes do; that parity accounts for the last character of several space-group symbols.
Fig. 8 Every pair of perpendicular planes in four groups, composed from the groups’ own operations and the product classified from its own intrinsic translation rather than predicted. Seven of the eight pairs give a screw and one does not, and the one is Pba2’s: both its planes are axial glides sliding along the direction the other faces, so neither has a component along their intersection and the two-fold along that line is a plain rotation. Pna2₁ is the contrast — one of its glides does slide along c, and the product is a 2₁.

The arithmetic is worth doing once because it explains the last character of four space-group symbols. If the first glide slides c₁ along the intersection and the second slides c₂, the product slides c₁ + c₂ — so the product is a screw exactly when c₁ + c₂ is a half, which is exactly when one of the two is a half and the other is zero. Both zero gives a rotation; both halves gives a whole cell, which is a lattice translation, so again a rotation.

That is a small parity argument and it accounts for a quarter of an entire arithmetic class.

Where the enumeration stops

Three limits.

The five letters are a naming convention over three geometric cases. There are not five kinds of glide; there are axial glides, of which there are up to three per plane depending on which cell vectors lie in it, one diagonal glide, and one diamond glide available only under centring. The letters a, b and c are the axial case named by direction, so the count of five is a count of symbols rather than of mechanisms. That is worth saying because “five glides” and “eleven screws” sound like comparable counts and are not: the eleven really are eleven distinct operations.

The d glide’s availability depends on the centring, not on the system. It appears in F- and I-centred groups, and the enumeration gives the reason — the half-diagonal has to be a lattice vector before a quarter of it can be a glide. There is no d glide in any primitive group, and the machinery here would refuse one: its square would not be a lattice translation and the closure would run away.

Nothing here says which glides a real crystal has. A glide is available if the group has it, and whether a structure adopts a group with one is a question about packing. Glide planes are common in molecular crystals because they let a molecule pack against a shifted copy of itself rather than a directly-facing one, which for most molecular shapes is denser — but that is an argument about shapes, not about symmetry, and this machinery has no access to it.

Who named them, and why the letters are what they are

The letters are Hermann’s and Mauguin’s, from the early 1930s, and they were chosen to be read rather than looked up: a, b and c name the axis the plane slides along, so the symbol contains the geometry.

n is for net, or diagonal depending on which account is being read, and it is the only letter of the five that is not the name of an axis. d is for diamond, after the structure, which is unusual — a symmetry operation named for a substance rather than for what it does. The reason is historical rather than principled: the operation was recognised in diamond’s structure before it was recognised as a general possibility, and by the time the enumeration made clear that it was one of a family the name had stuck.

There is a sixth letter in modern editions of the Tables, e, introduced in 1992 for a double glide — a plane that is simultaneously an a glide and a b glide, which happens when a centring translation makes both slides available on the same plane. It is not a new mechanism and it does not extend the enumeration above; it is a notational device for a case the old symbols described inconsistently, and five different space-group symbols were changed to use it. This site’s enumeration produces the five mechanisms and does not model the e convention, which is a choice about notation rather than about symmetry.

What both this rung and the last one keep running into is composition producing operations nobody chose. That is the next essay, and it is the reason a group is never given here as a list.

Three, because a rank-two lattice has four halves

The enumeration finds three candidates by trying them, and there is a one-line reason the number is three rather than some other small number — worth having, because it is the reason the answer does not change with the crystal system.

The slides available in a plane are the half-lattice vectors it contains, counted modulo the lattice. Write LL for the lattice vectors lying in the plane, a rank-two lattice. A glide’s slide must be half of one of them, and two slides differing by a whole lattice vector give the same operation, since a symmetry composed with a lattice translation is another symmetry of the same kind. So the possible slides are the elements of 12L\tfrac12 L modulo LL.

That quotient has exactly four elements. Halving each of two independent generators and taking all combinations gives nothing, half of one, half of the other, and half of their sum — the group of two binary digits, whatever the shape of the cell.

One of the four is the mirror. The zero slide is the operation that slides by nothing, so it is not a glide at all. Three remain, and they are the two axial glides and the diagonal glide, in every plane of every crystal system.

Centring is the only thing that changes the answer, because centring changes what LL is. If the half-diagonal is itself a lattice vector then LL is larger, its halves are quarters of the conventional diagonal, and a fourth kind of glide appears in the same quotient. The arithmetic is unchanged; the lattice it is performed on is not.

The letter the Tables added

There is a sixth letter in current use, and its history is a good illustration of how a symbol can be right and still mislead.

Some planes carry two glides at once. In a lattice centred on the face containing the plane, a plane can be simultaneously an aa-glide and a bb-glide — the same plane, two different slides, both genuine symmetries of the crystal, because the centring translation carries one onto the other. Nothing in the enumeration forbids it; the plane simply has more than one of the four elements above realised on it.

The old symbols named one and hid the other. A group whose plane was both was written with whichever letter convention preferred, so two groups differing in a real way could look alike, and one group could be written two ways by two people following the same rules.

The letter e names the pair. Introduced by the International Union of Crystallography in 1992 and standard in the Tables since, e means a double glide plane — both axial slides present. Five space-group symbols changed as a result: Abm2 became Aem2, Aba2 became Aea2, Cmma became Cmme, Ccca became Ccce, and Cmca became Cmce.

None of the groups changed. No symmetry was discovered and no enumeration was corrected; the symbols were made to say what the groups had always contained. That is the useful thing about the episode — a naming convention that reports one of several equally valid features is not a description, and the fix was to stop choosing.

And the older symbols are still everywhere. A structure published before the change carries the old letter, and databases hold both, so a reader comparing two entries has to know that Cmca and Cmce are the same group. That is the practical cost of the correction, and it is the ordinary cost of any correction to a notation that has been in use for a century.

What this makes readable

Essays that name this one as a prerequisite.

Named alongside this one

Essays reaching for the same objects. Nobody chose these; they are what the concept index makes visible.

What links here

The 8 essays that link to this one and share the most of its objects, of 11 that link here.

The objects this essay names

Each one links to every other essay that touches it.

CentringDiamond glideEnumerationGlide planeIntrinsic translationLattice translationMirror