Semi decision — where it appears
Named by 2 essays across one field — each of them below, with the objects they name alongside it.
How much room a hard question needs
No algorithm decides whether a set of tiles covers the plane. Every set of four or fewer tiles over two colours is nevertheless decided here, exhaustively, in under a second — because the sets that defeat the two half-searches have nowhere small to live.
The argument that closes eleven
Twenty-one vertex species satisfy the angle equation; a parity argument kills ten before anything is drawn, and the eleven survivors are all built. Asking the same question of tilings with two kinds of vertex, the parity argument evaporates — it constrains a walk in a graph one species decides, and two species decide the union of two graphs, which need not be bipartite. What is left is a search, and a search cannot close a count.
Named alongside it
The objects these essays reach for when they reach for this one.
Exhaustive searchAperiodic tile setAperiodicityCensusDecidabilityOrbitParityPlane groupRefutationRegular tilingTilingVertex figure